How many terms are there in the expansion of \(\rm \left(\frac{a^2}{b^2}+\frac{b^2}{a^2}+2\right)^{21}\) where a ≠ 0, b ≠ 0? 

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NDA 02/2021: Maths Previous Year paper (Held On 14 Nov 2021)
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  1. 21
  2. 22
  3. 42
  4. 43

Answer (Detailed Solution Below)

Option 4 : 43
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Detailed Solution

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Formula used:

If a and b are real numbers and n is a positive integer, then

(a + b)n = nC0 an + nC1 an - 1 b1 + .........  nCn bn  for \(\rm 0 \leq r \leq n\)

Total number of terms in (a + b)n = n + 1

 

Calculation:

We have to find the total number of terms in \(\rm \left(\frac{a^2}{b^2}+\frac{b^2}{a^2}+2\right)^{21}\) where a ≠ 0, b ≠ 0

⇒ \([{\rm \left(\frac{a}{b}+\frac{b}{a}\right)^{2}}]^{21}\)

⇒ \({\rm \left(\frac{a}{b}+\frac{b}{a}\right)^{42}}\)

∴ The total number of terms in the expression is 42 + 1 = 43.

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