How much work is done in moving a charge of 5 C across two points having a potential difference of 16 V?

This question was previously asked in
RRC Group D Previous Paper 14 (Held On: 25 Oct 2018 Shift 1)
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  1. 65 J
  2. 45 J
  3. 40 J
  4. 80 J

Answer (Detailed Solution Below)

Option 4 : 80 J
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Detailed Solution

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Option 4 is correct

CONCEPT:

  • Electric potential (V): The amount of work done to move a unit charge from a reference point (or infinity) to a specific point in an electric field without producing an acceleration is called electric potential at that point.

\({\rm{Electric\;potential\;}}\left( {\rm{V}} \right) = \frac{{{\rm{Work\;done\;}}\left( {\rm{W}} \right)}}{{{\rm{Charge\;}}\left( {\rm{q}} \right)}}\)

  • Electrostatic Potential Energy: The amount of work done to move a charged particle from infinity to a point in an electric field is known as the potential energy of that charged particle.

CALCULATION:

Given that:

Electric charge (q) = 5 C

Potential difference (V) = 16 V

Work done (W) = charge (q) × potential difference (V)

Work done (W) = 5 × 16 = 80 J

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