If ω is the angular speed of rotation and g is acceleration due to gravity, the height h of a watt governor is expressed as

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BPSC Lecturer ME Held on July 2016 (Advt. 35/2014)
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  1. h = ωg
  2. h = ω2g

Answer (Detailed Solution Below)

Option 1 :

Detailed Solution

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Concept:

Governor:

  • It is a device which controls the mean speed of the engine over a long period due to load fluctuation.
  • Governor has no influence over cyclic speed fluctuation

Watt Governor:

  • It is a type of centrifugal governor.
  • It is the simplest pendulum-type governor.
  • It is unsuitable for high-speed Engine.

 

The above figure shows the simple watt governor,

Let, m = mass of each ball, h = height of the governor, w = weight of each ball, ω = angular velocity of the arm ball and sleeve, T = tension in the arm, r = radial distance of ball-centre from spindle axis

Assuming the link to be massless and neglecting the friction of the sleeve, the mass m at A is in static equilibrium under the action of.

  • Weight w
  • Centrifugal force mrω2
  • Tension T in the upper link

The equilibrium of the ball provides

T × cos θ = mg

T × sin θ = mrω2

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