Question
Download Solution PDFIn 8085 microprocessor, the address for ‘TRAP’ input is
This question was previously asked in
ESE Electrical 2015 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 1 : 0024 H
Free Tests
View all Free tests >
ST 1: UPSC ESE (IES) Civil - Building Materials
6.1 K Users
20 Questions
40 Marks
24 Mins
Detailed Solution
Download Solution PDFFor 8085 the interrupt service routine address is given as:
RST 4.5 (TRAP)
ISR address: 4.5 × 8 = (36)10 = (0024) H
RST 5.5
ISR address: 5.5 × 8 = (44)10 = (002C) H
RST 6.5
ISR address: 6.5 × 8 = (52)10 = (0034) H
RST 7.5
ISR address: 7.5 × 8 = (60)10 = (003C) H
Latest UPSC IES Updates
Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students
Suggested Exams