In a batch Of 100 resistors Of 1kiloohm resistance, 80 numbers are within the required tolerance values and 11 numbers are below the required tolerance values, the remaining are above the required tolerance values. If two resistors are drawn one after the other without replacement, the probability of the first one drawn is below and the second one drawn is above the required tolerance value is 

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ISRO VSSC Technical Assistant Mechanical 14 July 2021 Official Paper
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  1. 0.01
  2. 0.09
  3. 0.11
  4. 0.89

Answer (Detailed Solution Below)

Option 1 : 0.01
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Explanation:

The total number of resistors is 100. Among them, 80 are within the required tolerance values, 11 are below, and the remaining (100 - 80 - 11 = 9) are above the required tolerance values.

The probability of drawing a resistor below the tolerance value first is the number of such resistors divided by the total number of resistors, which is 11/100.

After drawing one resistor, we have 99 resistors left. The probability of drawing a resistor above the tolerance value next is the number of such resistors divided by the remaining number of resistors, which is 9/99.

The probability of both events happening (drawing a resistor below the tolerance value first and drawing a resistor above the tolerance value next) is the product of the probabilities of the individual events, which is (11/100) * (9/99) = 0.01.

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