Question
Download Solution PDFA, B आणि C त्याच क्रमाने आळीपाळीने काम करत 15 दिवसात काम पूर्ण करू शकतात. A ची कार्यक्षमता B सारखीच आहे आणि C ची कार्यक्षमता A च्या समान आहे. त्यांनी C, A आणि B या क्रमाने आळीपाळीने काम केल्यास काम किती दिवसात पूर्ण होईल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
A ची कार्यक्षमता = B ची कार्यक्षमता
C ची कार्यक्षमता = A ची कार्यक्षमता
वापरलेले सूत्र:
एकूण काम = कार्यक्षमता x वेळ
गणना:
प्रश्नानुसार:
A ची कार्यक्षमता = B ची कार्यक्षमता = C ची कार्यक्षमता
A, B आणि C 15 दिवसात काम पूर्ण करू शकतात.
⇒ 3 दिवस = (1 + 1 + 1) = कामाची 3 युनिट्स
⇒ 3 x 5 = 15 दिवस = 3 x 5 = 15 कामाचे युनिट
आता, C, A आणि B आळीपाळीने काम करू शकतात,
⇒ (1 + 1 + 1) = कामाची 3 युनिट्स = 3 दिवस
⇒ 3 x 5 = 15 एकके काम = 3 x 5 = 15 दिवस
∴ योग्य उत्तर 15 दिवस आहे.
Last updated on Jun 13, 2025
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