Question
Download Solution PDFपाण्याखाली 65% घनफळ असलेला लाकडाचा एक तुकडा पाण्यावर तरंगतो, त्याची अंदाजे घनता (किग्रॅम/मी3 मध्ये) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF0.65 × 103 हे योग्य उत्तर आहे.
Key Points
पाण्याची घनता = 1000 किग्रॅम/मी3
लाकडाचे एकूण घनफळ V मानू.
पाण्याचे वजन = उत्प्रणोदन
लाकडाची घनता *V*g = 1000*0.65V*g
म्हणून, लाकडाची घनता =0.65 × 103 किग्रॅम/मी3.
Last updated on Jul 5, 2025
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