K चे मूल्य शोधा ज्यासाठी समीकरण x – Ky = 2, 3x + 2y = 5 मध्ये अद्वितीय निरसन आहे.

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UPTET 2018 Paper- 2 Maths & Science (Hindi - English/Sanskrit) Hinglish Solution
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  1. \(K \ne \frac {-2} 3\)
  2. \(K = \frac {2} 3\)
  3. \(K \ne \frac {2} 3\)
  4. \(K = \frac {-2} 3\)

Answer (Detailed Solution Below)

Option 1 : \(K \ne \frac {-2} 3\)
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संकल्पना:

पदावली विचारात घ्या: a 1 x + b 1 y + c = 0 आणि a 2 x + b 2 y + c = 0

जर 1/a2 ≠ b1/b2 असेल तर प्रणालीच्या स्थितीत अद्वितीय निरसन आहे

जर a1/a2 = b1/b2 = c1/c2 असेल तर प्रणालीच्या स्थितीत अनंत निरसन आहे

जर

a1/a2 = b1/b2 ≠ c1/c2

 

असेल तर प्रणालीसाठी स्थितीचे कोणतेही निरसन नाही

गणना:

असे समीकरण आहे   x – Ky = 2, 3x + 2y = 5

येथे, a 1 = 1, b 1 = -k, a 2 = 3,   b 2 = 2

1/3 -k/2

k -2/3

∴ K चे आवश्यक मूल्य -2/3 च्या समान नसावे

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