The calorific value of a fuel whose 1.5 kg of mass produces 67,500 kJ of heat on burning completely will be

This question was previously asked in
JTET 2012 (Mathematics & Science) Official Paper-II
View all JTET Exam Papers >
  1. 45,000 kJ/kg
  2. 30,000 kJ/kg
  3. 1,01,250 kJ/kg
  4. 1,01,250 kg/J

Answer (Detailed Solution Below)

Option 1 : 45,000 kJ/kg
Free
CTET Paper 2 Maths & Science (ज्ञानसंगम): Mini Live Test
1 Users
60 Questions 60 Marks 60 Mins

Detailed Solution

Download Solution PDF
The correct answer is 45,000 kJ/kg.

Key Points

  • Calorific value is the amount of heat energy produced on complete combustion of 1 kg of fuel.
  • The given fuel mass is 1.5 kg and it produces 67,500 kJ of heat.
  • Calorific value calculation involves dividing the total heat produced by the mass of the fuel.
  • Calorific value = Total heat produced / Mass of fuel = 67,500 kJ / 1.5 kg.
  • Therefore, the calorific value = 45,000 kJ/kg.

Additional Information

  • Calorific value is an important property of fuel that determines its efficiency.
  • Higher calorific value indicates a more efficient fuel.
  • Types of calorific value: There are two types: Gross Calorific Value (GCV) and Net Calorific Value (NCV).
Latest JTET Exam Updates

Last updated on Aug 30, 2024

-> The JTET Application Form can be submitted online by 30th August 2024.

-> The JTET Notification 2024 has been released. The Jharkhand TET is conducted as an eligibility test for the post of teacher (classes 1-8) in the schools of Jharkhand.  

-> The written examination has two papers. Paper I is conducted for the aspirants who wish to teach classes I to V class and  Paper II is for aspirants who wish to teach classes VI to VIII

-> Candidates can refer to the JTET Exam Previous Year Papers to get an idea of the type of questions asked in the exam and prepare accordingly.

Get Free Access Now
Hot Links: teen patti casino teen patti sweet master teen patti