The load shared by the member BC of the structure shown in figure below is :

F1  Akhil 20-12-21 savita D1

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UKPSC JE Civil 2013 Official Paper I
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  1. 2√3 t
  2. 3√2 t
  3. 4t
  4. 3t

Answer (Detailed Solution Below)

Option 3 : 4t
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UKPSC JE CE Full Test 1 (Paper I)
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Detailed Solution

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Calculation:

Given structure in below figure:

F1  Akhil 20-12-21 savita D1

Now draw the free body diagram of point B

F1 Shraddha Akhil 04.01.2022 D10

Hence, apply the equilibrium for forces in the vertical direction 

\(\sum F_y =0\)

FCB Sin30 = 2t

FCB \(\times \ {1 \over 2}\) = 2t

FCB = 4t

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