Question
Download Solution PDFThe load shared by the member BC of the structure shown in figure below is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given structure in below figure:
Now draw the free body diagram of point B
Hence, apply the equilibrium for forces in the vertical direction
\(\sum F_y =0\)
FCB Sin30 = 2t
FCB \(\times \ {1 \over 2}\) = 2t
FCB = 4t
Last updated on Mar 26, 2025
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