The number of moles of KMnO₄ needed to react completely with one mole of ferrous oxalate in acidic solution are :

Concept and Explanation:

• Reaction oF ferrous oxalate:
  • ​\(FeC_2O_4\ \rightarrow\ Fe^{3+}\ +2CO_2\ +3e-\)
• In acid medium MnO₄ changes to Mn²⁺ and consumes 5e-
  • \(MnO_4^- + 8H^+ + 5e^- \ \rightarrow \ Mn^{2+} + 4H_2O\)
• So,  3e^- will be consumed by 3/5 moles of KMnO₄

Conclusion:

Therefore, \(\frac{3}{5}\) moles of KMnO₄ needed to react completely with one mole of ferrous oxalate in acidic solution.