The stability factor (S) for common emitter circuit is given by _______ (treating base current constant)

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  1. S = α + β
  2. S = 1 + β
  3. S = 1 - β
  4. S = 2 + β

Answer (Detailed Solution Below)

Option 2 : S = 1 + β
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Detailed Solution

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Stability factor :

It is the measure of the stability of operating point in a transistor circuit.

S = \(\frac{\partial I_{C}}{\partial I_{CO}}\)\(\frac{1+\beta}{1-\beta(\frac{\partial I_{B}}{\partial I_{C}})}\)

Calculation :

Given :

IB = Constant

\(\frac{\partial I_{B}}{\partial I_{C}}\) = 0

S = 1 + \(\beta\)

Hence correct option is "2"

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