Question
Download Solution PDFThe type of hybridization and number of lone pair(s) of electrons of Xe in XeOF4, respectively, are
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In XeOF4, Xe is sp3 d2-hybridized.
The geometry of the molecule is octahedral, but the shape of the molecule is square pyramidal. According to VSEPR theory, it has one π bond. The remaining six electron pairs form an octahedron with one position occupied by a lone pair.
Here, Xe contains one lone pair of electrons.
Last updated on May 23, 2025
-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.
-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.
-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses.
-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.
-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025.