Two wattmeter readings in power measurement of a three-phase balanced lagging load were 2000 W and 1000 W. What is the reactive power in VAr of the load?

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MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper
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  1. 3000√3
  2. 1000√3
  3. 1000√2
  4. 3000√2

Answer (Detailed Solution Below)

Option 2 : 1000√3
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Detailed Solution

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Concept

The reactive power in power measurement of a three-phase using 2 wattmeters is given by:

\(Q={\sqrt{3}(W_1-W_2 )}\)

where, W1 and W2 are wattmeter readings

Calculation

Given, W1 = 2000 W

W2 = 1000 W

\(Q=\sqrt{3}(2000-1000)\)

Q = 1000√3 VAr

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