Question
Download Solution PDFWhat is the formula for the force of attraction (F) between two objects of masses M and m which lie at a distance d from each other, where G is the constant of proportionality called as universal gravitation constant?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKey Points
- The formula for the force of attraction (F) between two objects of masses M and m which lie at a distance d from each other is given by Newton's Law of Universal Gravitation.
- The formula is F = G (M × m) / d2.
- Here, G is the universal gravitation constant.
- This law states that every point mass attracts every other point mass by a force acting along the line intersecting both points.
- The force is directly proportional to the product of the two masses and inversely proportional to the square of the distance between the point masses.
Additional Information
- Newton's Law of Universal Gravitation was formulated by Sir Isaac Newton in 1687.
- The universal gravitation constant G is approximately equal to 6.674 × 10-11 N(m/kg)2.
- This law helps explain the motion of planets, moons, and artificial satellites.
- It is a cornerstone in the field of classical mechanics and has been confirmed by numerous experiments and observations.
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.