Bodmas Rule MCQ Quiz - Objective Question with Answer for Bodmas Rule - Download Free PDF
Last updated on May 17, 2025
Latest Bodmas Rule MCQ Objective Questions
Bodmas Rule Question 1:
The value of \(5\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4}\left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\) is
Answer (Detailed Solution Below)
Bodmas Rule Question 1 Detailed Solution
The table is,
\(5\frac{1}{3} ÷ 1\frac{2}{9} × \frac{1}{4}\left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\)
⇒ 16/3 ÷ 11/9 × 1/4 {10 + (3 × 5)/4}
⇒ 16/3 ÷ 11/9 × 1/4 (10 + 15/4)
⇒ 16/3 ÷ 11/9 × 1/4 × 55/4
⇒ 16/3 × 9/11 × 1/4 × 55/4
⇒ 1 × 3 × 1 × 5
⇒ 15
Hence, the correct answer is "15".
Bodmas Rule Question 2:
237 ÷ ____ = 23700
Answer (Detailed Solution Below)
Bodmas Rule Question 2 Detailed Solution
Given:
237 ÷ ____ = 23700
Formula Used:
Divisor = Dividend ÷ Quotient
Calculation:
Let the missing number be x.
Then, 237 ÷ x = 23700
⇒ x = 237 ÷ 23700
⇒ x = 1 / 100 = 0.01
∴ The missing number is 0.01
Bodmas Rule Question 3:
Value of \(\frac{1}{3}\) of \(\frac{1}{4}\) of \(\frac{1}{2}\) of \(\frac{1}{5}\) of 90840 is
Answer (Detailed Solution Below)
Bodmas Rule Question 3 Detailed Solution
Given:
Expression: \(\frac{1}{3}\) of \(\frac{1}{4}\) of \(\frac{1}{2}\) of \(\frac{1}{5}\) of 90840
Calculation:
\(\frac{1}{3}\) × \(\frac{1}{4}\) × \(\frac{1}{2}\) × \(\frac{1}{5}\) × 90840
⇒ \(\frac{1 × 1 × 1 × 1 × 90840}{3 × 4 × 2 × 5}\)
⇒ \(\frac{90840}{120}\)
⇒ 9084/12
⇒ 4542/6
⇒ 2271/3
⇒ 757
∴ The value is 757.
Bodmas Rule Question 4:
If 395 × x = 2765, then x is -
Answer (Detailed Solution Below)
Bodmas Rule Question 4 Detailed Solution
Given:
395 × x = 2765
Calculation:
To isolate x, we need to divide both sides of the equation by 395:
x = 2765 / 395
x = 7
∴ The value of x is 7.
Bodmas Rule Question 5:
The value of \(2^0\times \frac{1}{2}\times 2=\)
Answer (Detailed Solution Below)
Bodmas Rule Question 5 Detailed Solution
Given:
20 × 1/2 × 2
Formula used:
Exponential and Multiplication rules
Calculation:
20 × 1/2 × 2
⇒ 1 × 1
⇒ 1
∴ The correct answer is option (1).
Top Bodmas Rule MCQ Objective Questions
What will come in the place of question mark (?) in the following question?
\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 6 Detailed Solution
Download Solution PDFSolution:
We have to follow the BODMAS rule
Calculation:
\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)
\(⇒ ? = (243)^{\frac{2}{5}}\)
\(⇒ ? = (3 × 3 × 3 × 3 × 3)^{2⁄5}\)
\(⇒ ? = (3^5)^{2⁄5}\)
⇒ ? = 32
∴ ? = 9Find the value of:
\(\frac{{\left( {0.0112 - 0.0012} \right)\;of\;0.14\; + \;0.25\; \times \;0.2}}{{0.02\; \times \;0.01}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 7 Detailed Solution
Download Solution PDFWhat will come in place of the question mark ‘?’ in the following question?
(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)Answer (Detailed Solution Below)
Bodmas Rule Question 8 Detailed Solution
Download Solution PDFConcept used:
ax × ay = ax + y
ax ÷ ay = ax - y
Calculation:
(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)
⇒ 46 ÷ (64)4 × 2564 = (4)(? + 4)
⇒ 46 ÷ (43)4 × (44)4 = (4)(? + 4)
⇒ 4(6 + 16 - 12) = (4)(? + 4)
⇒ 410 = (4)(? + 4)
So, ? + 4 = 10
⇒ ? = 10 - 4
∴ ? = 6What should come at the place of ‘?’ in the following question?
1251/3 × 271/3 × 1254/3 = 15 × 5?Answer (Detailed Solution Below)
Bodmas Rule Question 9 Detailed Solution
Download Solution PDFFollow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,
Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,
Step-2- Then any mathematical 'Of' or 'Exponent' must be solved,
Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
1251/3 × 271/3 × 1254/3 = 15 × 5?
⇒ 5 × 3 × 54 = 15× 5x
⇒ 15 × 5 4 = 15× 5x
⇒ x = 4
Hence option 4 is correct.
What should come in the place of question mark (?) in the following question?
\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
Answer (Detailed Solution Below)
Bodmas Rule Question 10 Detailed Solution
Download Solution PDFConcept used:
Follow BODMAS rule to solve this question, as per the order given below:
\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{\frac{{729}}{{1000}}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{{{\left( {\frac{9}{{10}}} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow {\rm{\;}}\frac{{7.2}}{{\sqrt[3]{{{{\left( {0.9} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
\(\Rightarrow \frac{{7.2}}{{0.9}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)
⇒ 8 = (?)3/(2)3
⇒ (2)3 = (?)3/(2)3
⇒ 23 × 23 = (?)3
⇒ 43 = (?)3
⇒ ? = 4
∴ The value of ? is 4.Simplify (957 + 932)2 - 4 × 957 × 932.
Answer (Detailed Solution Below)
Bodmas Rule Question 11 Detailed Solution
Download Solution PDFShortcut Trick Formula:
(a+b)2 - 4ab = (a-b)2
Calculation:
(957 + 932)2 - 4 × 957 × 932
= (957 - 932)2
= 252 = 625
Alternate Method GIVEN:
\(( 957 + 932 )^2\) - 4 × 957 × 932.
FORMULA USED:
BODMAS
CALCULATION :
⇒ \((1889)^2\) - 4 × 957 × 932
⇒ 3568321 - 4 × 957 × 932
⇒ 3568321 - 3567696 = 625
∴ The value is 625.
1962 × 56 ÷ 145 × 1021 = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 12 Detailed Solution
Download Solution PDFConcept used:
Calculation:
1962 × 56 ÷ 145 × 1021
⇒ (142)2 × (56/145) × 1021
⇒ [144 × (56/145)] × 1021
⇒ (56/14) × 1021
⇒ 4 × 1021 = 4084
∴ The answer will be 4084.
63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}] = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 13 Detailed Solution
Download Solution PDFUsing BODMAS rule:
⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}]
⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + 2}]
⇒ 63 - (42) ÷ 21
⇒ 61What approximate value should come in place of question mark ‘?’ in the following question?
1132.757 – 2315.996 – 1753.829 + 2 × 2846.639 = ?
Answer (Detailed Solution Below)
Bodmas Rule Question 14 Detailed Solution
Download Solution PDF1132.757 – 2315.996 – 1753.829 + 2 × 2846.639
= 1133 – 2316 – 1754 + 5694
= (1133 + 5694) – (2316 + 1754 )
= 6827 – 4070
= 2757
\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right]= ? \)
Answer (Detailed Solution Below)
Bodmas Rule Question 15 Detailed Solution
Download Solution PDFConcept used:
Calculation:
\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right] \)
⇒ 56 ÷ [(1/3){15 + 12 - (9 + 6 - 12)}]
⇒ 56 ÷ [(1/3){15 + 12 - (15 - 12)}]
⇒ 56 ÷ [(1/3){15 + 12 - 3}]
⇒ 56 ÷ [(1/3){27 - 3}]
⇒ 56 ÷ [(1/3)(24)]
⇒ 56 ÷ 8
⇒ 7
∴ ? = 7
Important Points
If in any simplification problem there is ( ̅ ) bar sign above any operation then we should perform the operation at the beginning, whatever the operation is. Then we will follow the chart given above.