Bodmas Rule MCQ Quiz - Objective Question with Answer for Bodmas Rule - Download Free PDF

Last updated on May 17, 2025

BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction. It is a prescribed order of operations on given mathematical expressions that ensure the most accurate result. It may take a while for the BODMAS rule to sink into your practice. Practice these BODMAS rule MCQs Quiz selected by Testbook’s team of experts and never arrive at a wrong answer for any question in the examination. Get tips, tricks and insights into the solutions of BODMAS rule objective questions.

Latest Bodmas Rule MCQ Objective Questions

Bodmas Rule Question 1:

The value of \(5\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4}\left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\) is

  1. 15
  2. 67/25
  3. 128/11
  4. 128/99
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : 15

Bodmas Rule Question 1 Detailed Solution

The table is,

qImage21050

\(5\frac{1}{3} ÷ 1\frac{2}{9} × \frac{1}{4}\left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\)

⇒ 16/3 ÷ 11/9 × 1/4 {10 + (3 × 5)/4}

⇒ 16/3 ÷ 11/9 × 1/4 (10 + 15/4)

⇒ 16/3 ÷ 11/9 × 1/4 × 55/4

⇒ 16/3 × 9/11 × 1/4 × 55/4

⇒ 1 × 3 × 1 × 5

⇒ 15

Hence, the correct answer is "15".

Bodmas Rule Question 2:

237 ÷ ____ = 23700

  1. 10
  2. 0.01
  3. 0.1
  4. 100

Answer (Detailed Solution Below)

Option 2 : 0.01

Bodmas Rule Question 2 Detailed Solution

Given:

237 ÷ ____ = 23700

Formula Used:

Divisor = Dividend ÷ Quotient

Calculation:

Let the missing number be x.

Then, 237 ÷ x = 23700

⇒ x = 237 ÷ 23700

⇒ x = 1 / 100 = 0.01

∴ The missing number is 0.01

Bodmas Rule Question 3:

Value of  \(\frac{1}{3}\)  of \(\frac{1}{4}\) of \(\frac{1}{2}\) of \(\frac{1}{5}\) of 90840 is

  1. 753
  2. 758
  3. 757
  4. None of these 

Answer (Detailed Solution Below)

Option 3 : 757

Bodmas Rule Question 3 Detailed Solution

Given:

Expression: \(\frac{1}{3}\) of \(\frac{1}{4}\) of \(\frac{1}{2}\) of \(\frac{1}{5}\) of 90840

Calculation:

\(\frac{1}{3}\) × \(\frac{1}{4}\) × \(\frac{1}{2}\) × \(\frac{1}{5}\) × 90840

\(\frac{1 × 1 × 1 × 1 × 90840}{3 × 4 × 2 × 5}\)

\(\frac{90840}{120}\)

⇒ 9084/12

⇒ 4542/6

⇒ 2271/3

⇒ 757

∴ The value is 757.

Bodmas Rule Question 4:

If 395 × x = 2765, then x is -

  1. 7
  2. \(\frac{1}{7}\)
  3. 2370
  4. 3160

Answer (Detailed Solution Below)

Option 1 : 7

Bodmas Rule Question 4 Detailed Solution

- www.bijoux-oeil-de-tigre.com

Given:

395 × x = 2765

Calculation:

To isolate x, we need to divide both sides of the equation by 395:

x = 2765 / 395

x = 7

∴ The value of x is 7.

Bodmas Rule Question 5:

The value of \(2^0\times \frac{1}{2}\times 2=\)

  1. 1
  2. 0
  3. 2
  4. None of these

Answer (Detailed Solution Below)

Option 1 : 1

Bodmas Rule Question 5 Detailed Solution

Given:

20 × 1/2 × 2

Formula used:

Exponential and Multiplication rules

Calculation:

20 × 1/2 × 2

⇒ 1 × 1

⇒ 1

∴ The correct answer is option (1).

Top Bodmas Rule MCQ Objective Questions

What will come in the place of question mark (?) in the following question?

\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)

  1. 3
  2. 7
  3. 6
  4. 8
  5. 9

Answer (Detailed Solution Below)

Option 5 : 9

Bodmas Rule Question 6 Detailed Solution

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Solution:

We have to follow the BODMAS rule

quesImage82

Calculation:

\(? = \sqrt[5]{{{{\left( {243} \right)}^2}}}\)

 

\(⇒ ? = (243)^{\frac{2}{5}}\)

\(⇒ ? = (3 × 3 × 3 × 3 × 3)^{2⁄5}\)

\(⇒ ? = (3^5)^{2⁄5}\)

⇒ ? = 32

∴ ? = 9

Find the value of:

\(\frac{{\left( {0.0112 - 0.0012} \right)\;of\;0.14\; + \;0.25\; \times \;0.2}}{{0.02\; \times \;0.01}}\)

  1. 257
  2. 25.7
  3. 2.57
  4. 0.0257

Answer (Detailed Solution Below)

Option 1 : 257

Bodmas Rule Question 7 Detailed Solution

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\(\begin{array}{l} \frac{{\left( {0.0112 - 0.0012} \right)\;of\;0.14\; + \;0.25\; \times \;0.2}}{{0.02\; \times \;0.01}}\\ = \;\frac{{\left( {0.01} \right)of\;0.14\; + \;0.05}}{{0.0002}}\\ = \;\frac{{0.01\; \times \;0.14\; + \;0.05}}{{0.0002}}\\ \; = \;\frac{{0.0014\; + \;0.05}}{{0.0002}}\\ = \;\frac{{0.0514}}{{0.0002}}\\ = \;257 \end{array}\)

What will come in place of the question mark ‘?’ in the following question?

(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)

  1. 8
  2. 12
  3. 6
  4. 14
  5. 10

Answer (Detailed Solution Below)

Option 3 : 6

Bodmas Rule Question 8 Detailed Solution

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Concept used:

ax × ay = ax + y

ax ÷ ay = ax - y

BODMAS

Calculation:

(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (2 × 2)(? + 4)

⇒ 46 ÷ (64)4 × 2564 = (4)(? + 4)

⇒ 46 ÷ (43)4 × (44)4 = (4)(? + 4)

⇒ 4(6 + 16 - 12) = (4)(? + 4)

⇒ 410 = (4)(? + 4)

So, ? + 4 = 10

⇒ ? = 10 - 4

∴ ? = 6

What should come at the place of ‘?’ in the following question?

1251/3 × 271/3 × 1254/3 = 15 × 5?

  1. 5
  2. 3
  3. 1
  4. 2
  5. 4

Answer (Detailed Solution Below)

Option 5 : 4

Bodmas Rule Question 9 Detailed Solution

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Follow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,

Step-2-  Then any mathematical 'Of' or 'Exponent' must be solved,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

1251/3 × 271/3 × 1254/3 = 15 × 5?

⇒ 5 × 3 × 54 = 15× 5x

⇒ 15 × 5 4 = 15× 5x

⇒ x = 4

Hence option 4 is correct.

What should come in the place of question mark (?) in the following question?

\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

  1. 4
  2. 5
  3. 6
  4. 8
  5. 9

Answer (Detailed Solution Below)

Option 1 : 4

Bodmas Rule Question 10 Detailed Solution

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Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

image (4) (1)

\(\frac{{7.2}}{{\sqrt[3]{{0.729}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{\frac{{729}}{{1000}}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{\sqrt[3]{{{{\left( {\frac{9}{{10}}} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow {\rm{\;}}\frac{{7.2}}{{\sqrt[3]{{{{\left( {0.9} \right)}^3}}}}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

\(\Rightarrow \frac{{7.2}}{{0.9}} = \frac{{{{\left( ? \right)}^3}}}{{{{\left( 2 \right)}^3}}}\)

⇒ 8 = (?)3/(2)3

⇒ (2)3 = (?)3/(2)3

⇒ 23 × 23 = (?)3

⇒ 43 = (?)3

⇒ ? = 4

∴ The value of ? is 4.

Simplify (957 + 932)2 - 4 × 957 × 932.

  1. 576
  2. 676
  3. 529
  4. 625

Answer (Detailed Solution Below)

Option 4 : 625

Bodmas Rule Question 11 Detailed Solution

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Shortcut Trick Formula:

(a+b)- 4ab = (a-b)2

Calculation:

(957 + 932)2 - 4 × 957 × 932

= (957 - 932)2

= 252 = 625

Alternate Method GIVEN:

\(( 957 + 932 )^2\) - 4 × 957 × 932.

FORMULA USED:

BODMAS 

qImage25485

CALCULATION :

⇒ \((1889)^2\) - 4 × 957 × 932 

⇒ 3568321 - 4 × 957 × 932 

⇒ 3568321 - 3567696  =  625 

∴ The value is 625.

1962 × 56 ÷ 145 × 1021 = ?

  1. 4074
  2. 4064
  3. 4084
  4. 4054

Answer (Detailed Solution Below)

Option 3 : 4084

Bodmas Rule Question 12 Detailed Solution

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Concept used:

5ee101ce98b8e70d1cd387cc 16317287923321

Calculation:

1962 × 56 ÷ 145 × 1021 

⇒ (142)2 × (56/145) × 1021 

⇒ [144 × (56/145)] × 1021 

⇒ (56/14) × 1021 

⇒ 4 × 1021 = 4084

∴ The answer will be 4084.

63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}] = ?

  1. 65
  2. 60
  3. -60
  4. 61

Answer (Detailed Solution Below)

Option 4 : 61

Bodmas Rule Question 13 Detailed Solution

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BODMAS

Using BODMAS rule:

⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + (- 2)(- 1)}]

⇒ 63 - (- 3)(- 2 - 8 - 4) ÷ [3 {5 + 2}]

⇒ 63 - (42) ÷ 21

⇒ 61

What approximate value should come in place of question mark ‘?’ in the following question?

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639 = ?

  1. 2746
  2. 2757
  3. 2656
  4. 2646
  5. None of these

Answer (Detailed Solution Below)

Option 2 : 2757

Bodmas Rule Question 14 Detailed Solution

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1132.757 – 2315.996 – 1753.829 + 2 × 2846.639

= 1133 – 2316 – 1754 + 5694

= (1133 + 5694) – (2316 + 1754 )

= 6827 – 4070

= 2757

\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right]= ? \)

  1. 12
  2. 4032
  3. 7
  4. 448

Answer (Detailed Solution Below)

Option 3 : 7

Bodmas Rule Question 15 Detailed Solution

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Concept used:

BODMAS

Calculation:

\(56 \div \left[\frac{1}{3}\left\{ {15 + 12 - \left( {9 + 6 - \overline {5 + 7} } \right)} \right\} \right] \)

⇒ 56 ÷ [(1/3){15 + 12 - (9 + 6 - 12)}]

⇒ 56 ÷ [(1/3){15 + 12 - (15 - 12)}]

⇒ 56 ÷ [(1/3){15 + 12 - 3}]

⇒ 56 ÷ [(1/3){27 - 3}]

⇒ 56 ÷ [(1/3)(24)]

⇒ 56 ÷ 8

⇒ 7 

∴ ? = 7

Important Points

If in any simplification problem there is (  ̅  ) bar sign above any operation then we should perform the operation at the beginning, whatever the operation is. Then we will follow the chart given above. 

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