Stationary Object with angle of elevation MCQ Quiz - Objective Question with Answer for Stationary Object with angle of elevation - Download Free PDF
Last updated on May 23, 2025
Latest Stationary Object with angle of elevation MCQ Objective Questions
Stationary Object with angle of elevation Question 1:
A pole 10 m long rests slantly against a vertical wall AB making an angle 30º with the horizontal (ground). Find how far the foot of the pole is from the wall (in metres).
Answer (Detailed Solution Below)
Stationary Object with angle of elevation Question 1 Detailed Solution
Given:
Length of the pole (hypotenuse) = 10 m
Angle with the horizontal = 30º
Formula Used:
cos(θ) = adjacent / hypotenuse
Where θ is the angle with the horizontal and the adjacent is the distance from the foot of the pole to the wall.
Calculations:
cos 30º = b/h = BC / AC
⇒ √3 / 2 = BC / 10
⇒ BC = 10 × √3 / 2
⇒ BC = 5√3 m
∴ The correct answer is option (4).
Stationary Object with angle of elevation Question 2:
A person standing at a distance looks at a building having a height of 1000 metres. The angle between the top of the building and the ground is 30°. At what approximate distance (in metres) is the person standing away from the building.
Answer (Detailed Solution Below)
Stationary Object with angle of elevation Question 2 Detailed Solution
Given:
Height of building = 1000 m
Angle of elevation = 30°
Formula used:
Tan θ = perpendicular/Base = P/B
Tan 30° = 1/√3
Value of √3 = 1.732
Calculation:
Tan 30° = AB/BC
⇒ 1/√3 = 1000/BC
⇒ BC = 1000√3
⇒ BC = 1000 × 1.732 = 1732 m
∴ The correct answer is 1732 m.
Top Stationary Object with angle of elevation MCQ Objective Questions
A person standing at a distance looks at a building having a height of 1000 metres. The angle between the top of the building and the ground is 30°. At what approximate distance (in metres) is the person standing away from the building.
Answer (Detailed Solution Below)
Stationary Object with angle of elevation Question 3 Detailed Solution
Download Solution PDFGiven:
Height of building = 1000 m
Angle of elevation = 30°
Formula used:
Tan θ = perpendicular/Base = P/B
Tan 30° = 1/√3
Value of √3 = 1.732
Calculation:
Tan 30° = AB/BC
⇒ 1/√3 = 1000/BC
⇒ BC = 1000√3
⇒ BC = 1000 × 1.732 = 1732 m
∴ The correct answer is 1732 m.
Stationary Object with angle of elevation Question 4:
A person standing at a distance looks at a building having a height of 1000 metres. The angle between the top of the building and the ground is 30°. At what approximate distance (in metres) is the person standing away from the building.
Answer (Detailed Solution Below)
Stationary Object with angle of elevation Question 4 Detailed Solution
Given:
Height of building = 1000 m
Angle of elevation = 30°
Formula used:
Tan θ = perpendicular/Base = P/B
Tan 30° = 1/√3
Value of √3 = 1.732
Calculation:
Tan 30° = AB/BC
⇒ 1/√3 = 1000/BC
⇒ BC = 1000√3
⇒ BC = 1000 × 1.732 = 1732 m
∴ The correct answer is 1732 m.
Stationary Object with angle of elevation Question 5:
A pole 10 m long rests slantly against a vertical wall AB making an angle 30º with the horizontal (ground). Find how far the foot of the pole is from the wall (in metres).
Answer (Detailed Solution Below)
Stationary Object with angle of elevation Question 5 Detailed Solution
Given:
Length of the pole (hypotenuse) = 10 m
Angle with the horizontal = 30º
Formula Used:
cos(θ) = adjacent / hypotenuse
Where θ is the angle with the horizontal and the adjacent is the distance from the foot of the pole to the wall.
Calculations:
cos 30º = b/h = BC / AC
⇒ √3 / 2 = BC / 10
⇒ BC = 10 × √3 / 2
⇒ BC = 5√3 m
∴ The correct answer is option (4).