Traffic Engineering MCQ Quiz in मराठी - Objective Question with Answer for Traffic Engineering - मोफत PDF डाउनलोड करा
Last updated on Mar 11, 2025
Latest Traffic Engineering MCQ Objective Questions
Top Traffic Engineering MCQ Objective Questions
Traffic Engineering Question 1:
The free mean speed on a roadway is found to be 80 kmph. Under stopped condition, the average spacing between the vehicles is 6.9 m. What is the capacity flow ?
Answer (Detailed Solution Below)
Traffic Engineering Question 1 Detailed Solution
Concept:
Free Mean Speed:
From the speed-density diagram, it can be defined as the maximum speed at which the number of vehicles in a unit length is zero i.e. density is zero.
Density:: It can be defined as the number of vehicles per unit length. The unit of measurement is vehicles/km.
Jam Density: From the speed-density relation and flow-density curve, it can also be seen that it is the maximum density at which there is no flow on the road.
Traffic Flow: The number of vehicles passing through a particular point in a certain time interval is defined as traffic flow. Also, the number of vehicles counted in one hour is called traffic flow (q).
The relation between k, u, and q is given below-
\({\bf{q}} = {\bf{k}} \times {\bf{u}}\;{\bf{veh}}/{\bf{hour}}\)
From the curves above, As long as the relation between density and speed is linear, it can be seen that maximum flow (or flow capacity) occurs at kj/2 and uf/2.
\({{\bf{q}}_{{\bf{max}}}} = \left( {\frac{{{{\bf{k}}_{\bf{j}}}}}{2}} \right)\left( {\frac{{{{\bf{u}}_{\bf{f}}}}}{2}} \right)\;{\bf{veh}}/{\bf{hour}}\)
Calculation:
Given
Uf = Free-flow speed = 80 kmph
Kj = Jam density
Kj = \(\frac{{1000}}{{S}}= \frac{{1000}}{{6.9}} \)
\({{\bf{q}}_{{\bf{max}}}} = \left( {\frac{{{{\bf{k}}_{\bf{j}}}}}{2}} \right)\left( {\frac{{{{\bf{u}}_{\bf{f}}}}}{2}} \right)\;{\bf{veh}}/{\bf{hour}}\)
\(Capacity = \frac{{1000 \times 80}}{4 \times 6.9} = 2898.55\) veh/hour/laneTraffic Engineering Question 2:
An isolated two-phase traffic signal is designed by Webster method, what will be the Optimum Signal cycle, if the critical flow ratio is 0.6 and the all red time required for pedestrian crossing is 10 seconds?
Answer (Detailed Solution Below)
Traffic Engineering Question 2 Detailed Solution
Concept:
As per Webster's method, the optimum cycle is given by,
\(C_o=\frac{{1.5L + 5}}{{1 - Y}}\)
Where, Co = Optimum signal cycle
L = 2n + R
n = Number of phases, R = All red time
Y = Critical flow ratio
Y = y1 + y2 (the value of Y should be less than 1)
Here, y1 = q1/s1 and y2 = q2/s2
Calculation:
Given,
n = 2, Y = 0.6, R = 10 second
L = 2n + R = 2 × 2 + 10 = 14 Second
So, as per Webster's method
\(C_o=\frac{{1.5L + 5}}{{1 - Y}}\)
Co = \(\frac{(1.5 × 14 + 5)}{(1-0.6)}\)
Co = 65 Second
Traffic Engineering Question 3:
The diameter of a mandatory sign disc must be
Answer (Detailed Solution Below)
Traffic Engineering Question 3 Detailed Solution
Explanation:
Traffic sign:
In older days road locomotives carried a red flag by day and a red lantern by night. Safety is the prime motive of every traffic.
Kinds of road signs,
- Mandatory
- Cautionary and
- Informatory
Mandatory sign:
Violation of mandatory signs can lead to penalties. Example: Stop, Give way, limits, prohibited, no parking, and compulsory sign.
The diameter of a mandatory sign disc must be 60 cm.
Overtaking Prohibited
Cautionary signs:
Cautionary/ warning signs are, especially for safety. Do's and don'ts for pedestrians, cyclists, bus passengers, and motorists.
Information signs:
Information signs are especially beneficial to the passengers and two-wheelers.
Traffic Engineering Question 4:
Two major roads with two lanes each are crossing in an urban area to form an uncontrolled intersection. The number of conflict points when both the roads are two way is X, and when both the roads are one way is Y. The ratio of conflict points X to Y is:
Answer (Detailed Solution Below)
Traffic Engineering Question 4 Detailed Solution
Explanation:
For the intersection of two-lane two-way roads from both sides:
Major conflicting points = 16, Minor conflicting points = 8 and thus total conflicting points (X) = 24
For the intersection of two-lane one-way rod and two-lane one-way road:
Major conflicting points = 4 Minor conflicting points = 2 and thus total conflicting points (Y) = 6
So, X/Y = 24/6 = 4
Additional Information
For the intersection of a two-lane one-way rod from both sides:
Major conflicting points = 7 Minor conflicting points = 4 and thus total conflicting points = 11
Important Points:
Number of lanes |
Number of potential conflicts |
|||
Road A |
Road B |
Both roads Two-way |
A – One-way B- Two-way |
Both-roads One-way |
2 |
2 |
24 |
11 |
6 |
2 |
4 |
32 |
17 |
10 |
4 |
4 |
44 |
25 |
18 |
Traffic Engineering Question 5:
In which type of traffic signal system do signals along a given road shows the same indication (green, red, etc.) at the same time?
Answer (Detailed Solution Below)
Traffic Engineering Question 5 Detailed Solution
Explanation:
There are four general types of co-ordination of signals for road network:
Simultaneous system: In this system all the signals along a given road always show the same indication (green, red etc.) at the same time. As the division of cycle is also the same at all intersections, this system does not work satisfactorily.
Alternate system: In this system, alternate signals or group of signals show opposite indications in a route at the same time. This system is also operated by a single controller but by reversing the red and green indicator connections at successive systems. This system is generally considered to be more satisfactory than simultaneous system.
Simple progressive system: In this system, the signal phases controlling “Go” indications along this road is scheduled to work at the predetermined time schedule.
Flexible progressive system: In this system it is possible to automatically vary the length of cycle, cycle division and the time scheduled at each signalized intersection with the help of a computer. This system is most efficient among all four systems.Traffic Engineering Question 6:
The increase in traffic Volume, due to the general increase in the number of transport Vehicles from year to year is known as,
Answer (Detailed Solution Below)
Traffic Engineering Question 6 Detailed Solution
Concept:
Normal traffic growth
It is the increase in traffic volume due to the cumulative annual increases in the numbers and usage of motor vehicles.
Normal Traffic Growth = Current Traffic (Existing Traffic) ×TPF
and
TPF(Traffic Projection Factor)
\(𝑇𝑃𝐹 = (1 + 𝑟)^{x+n}\)
Where: r = Annual rate of traffic increase (0 – 10%), n = design life in years (20 – 50 years), x = construction period in years (2 – 4 years)
Induced Traffic
It consists of traffic that did not exist previously in any form and which results from the construction of the new facility, and of the traffic composed of extra journeys by existing vehicles as a result of the increased convenience and reduced travel time via the new road.
Converted traffic
It is that which results from changes in mode of travel; for instance, the building of a motorway may make a route so attractive that traffic that previously made the same trip by bus or rail may now do so by car.
Development Traffic
It is the future traffic volume component that is due to developments on land adjacent to a new road over and above that which would have taken place had the new road not been built.
Traffic Engineering Question 7:
Identify the traffic signs which do not come under the category of a Regulatory Sign.
Answer (Detailed Solution Below)
Traffic Engineering Question 7 Detailed Solution
Explanation:
Classification of traffic signs:
1) Mandatory/Regulatory sign:
- The regulatory or mandatory signs are used to inform the road Users of certain laws and regulations to provide safety and free flow to traffic.
- Shape: Circular
Note:
Exception: Stop and Give way sign
The stop sign is octagonal in shape and the Give Way sign has the shape of an inverted triangle.
2) Warning sign:
- These signs are used to warn the road users at sufficient distance in advance about the impending road condition.
- Warning signs are also known as cautionary signs.
- Shape: Triangle
3) Informatory sign:
- Informatory signs are provided to guide the road user about the routes, destination, and to provide information that makes travel easier, safe, and pleasant.
- Shape: Rectangle
Traffic Engineering Question 8:
What will be the theoretical maximum capacity for a single lane of highway if the speed of the traffic stream is 40 kmph? (round off 10 units)
Answer (Detailed Solution Below)
Traffic Engineering Question 8 Detailed Solution
Explanation:
The theoretical maximum capacity for a single lane is given by,
C = (1000V)/S
Where,
C is capacity is vehicle/hr
V = speed in km/hr
S = minimum clear distance between two vehicles and it is given as:
S = 0.2V + 6 (if V is in kmph)
(or)
S = 0.7v + 6 (if v is in m/s)
Calculation:
Given: V = 40 km/hr
S = 0.2 × 40 + 6 = 14 m
The capacity for a single lane is:
C = 1000 × 40/14
C = 2857 Veh/hr
C≈ 2860 Veh/hr
Traffic Engineering Question 9:
Calculate the capacity (vehicle per hour) of the road when reaction time of the driver is 2 seconds. The design speed is 80 kmph and average length of the vehicle is 6 m. Take coefficient of faction is 0.35.
Answer (Detailed Solution Below)
Traffic Engineering Question 9 Detailed Solution
Explanation
Road capacity in general refers to the maximum traffic flow obtainable on a given roadway using all available lanes; usually expressed in vehicles per hour or vehicles per day.
This depends upon several factors
- Traffic conditions
- Road geometry characteristics
- Environmental factors
Calculation:
Capacity = \(\frac{1000V}{S}\)
S = SSD+L ,SSD = Stopping side distance , L = Length of the vehicle
V=Design speed
Here V = 80 Kmph L= 6 m .f= 0.35
Now SSD = v × t+ \(\frac{v^2}{2× g× f}\)
Here v = design speed in m/s = \(\frac{80}{3.6}\) = 22.22 m/s
So SSD = 22.22 × 2 + \(\frac{22.22^2}{2\times 9.81\times0.35}\) = 116.33 m
Put in the formula of capacity C= \(\frac {1000\times80}{116.338+6}\) = 653
Traffic Engineering Question 10:
As per IRC, what shall be the maximum length of truck and trailer combination of road vehicle?
Answer (Detailed Solution Below)
Traffic Engineering Question 10 Detailed Solution
According to IRC,
Dimension Of Vehicle |
Details |
Maximum dimensions (excluding front & Rear bumpers), m |
Width |
All vehicles |
2.50 |
Height |
(a) Single-decked vehicle for normal application |
3.80 |
(b) Double-decked vehicle |
4.75 |
|
Length |
(a) Single-unit truck with two or more axles (types 2, 3) |
11.00 |
(b) Single-unit bus with two or more axles (types 2, 3 |
12.00 |
|
(c) Semi-trailer tractor combinations (types 2 – S1, 2 – S2, 3 – S1, 3 – S2) |
16.00 |
|
(d) Tractor and trailer combinations (types 2 – 2, 3 – 2, 2 – 3, 3 - 3) |
18.00 |