Question
Download Solution PDFA 3-phase, 10 kV distribution line delivers power to a load at a 0.8 power factor lagging. If the current is 50 A, and the load resistance and reactance per km are 0.15 Ω and 0.2 Ω, respectively, for a 400 m line, what is the approximate voltage drop per phase (in V/phase)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The voltage drop per phase (in V/phase) is given by:
V = I × ZT
where, V = Voltage drop
I = Current
ZT = Total Impedance
Calculation
Given, cosϕ = 0.8 lag → ϕ = 36.86°
I = 50∠-36.86°
Length = 400 m = 0.4 km
ZT = (0.15 + j0.2) × 0.4
ZT = (0.06 + j0.08) Ω/km
V = (50∠-36.86°) × (0.06 + j0.08)
V = 50(0.8 - j0.6) × (0.06 + j0.08)
V = (40 - j30) × (0.06 + j0.08)
V = 4.8 + j1.4
Last updated on Jun 7, 2025
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