Question
Download Solution PDFA coil having pure inductance of 0.2 H is connected in series with a 60 μF capacitor. The voltage across the circuit is 230V, 50Hz. The active power consumed by the circuit is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 3):(0 watts)
Concept:
The active power is the amount of the total electric power in an AC electric circuit which actually consumed or utilized. It is also called as true power or real power. The active power is measured in Watts (W).
An LC circuit, also called a resonant circuit, tank circuit, or tuned circuit, is an electric circuit consisting of an inductor, represented by the letter L, and a capacitor, represented by the letter C, connected together.
An LC circuit is an idealized model since it assumes there is no dissipation of energy due to resistance.
Calculation:
Given
L = 0.2 H pure inductor
C = 60 μF
R = 0
The given circuit is considered to be ideal tank circuit no power will be dissipated so active power is zero
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