A pure Si crystal has 6 × 1028 atoms m-3. It is doped by 1 ppm concentration of pentavalent As. Then the number of electrons and holes are:

(Given that ni = 1.5 × 1016 m-3)

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  1. 6 × 1028 m-3 and 3.75 × 109 m-3
  2. 6 × 1025 m-3 and 3.75 × 1019 m-3
  3. 6 × 1022 m-3 and 3.75 × 109 m-3
  4. 6 × 1022 m-3 and 3.75 × 1019 m-3

Answer (Detailed Solution Below)

Option 3 : 6 × 1022 m-3 and 3.75 × 109 m-3
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Detailed Solution

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Concept:

Extrinsic semicodutor:

  • Extrinsic semiconductors are semiconductors that are doped with specific impurities.
  • The  modifies the electrical properties of the semiconductor and makes it more suitable for electronic devices such as diodes and transistors.
  • Two types of extrinsic semiconductors: N-type and P-type
  • The electron and hole concentration in a semiconductor is in thermal equilibrium. ni2 = ne × nh

Calculation:

Given,

ni = 1.5 × 1016 m-3 

The number of atoms in a pure Si crystal =  6 × 1028 atoms m-3.

We know that 1 ppm = 10-6 

Hence, the number of electrons, \(n_e=\frac{6× 10^{28}}{10^6}\)

ne = 6 × 1022 m-3

The electron and hole concentration in a semiconductor is in thermal equilibrium.

ni2 = ne × nh

\(\Rightarrow n_h=\frac{n_i^2}{n_e}\)

\(\Rightarrow n_h=\frac{(1.5\times 10^{16})^2}{6\times 10^{22}}=3.75\times 10^{9}~m^{-3}\)

Additional Information

 Intrinsic semiconductor:

  • Semiconductors that are chemically pure, in other words, free from impurities are termed intrinsic semiconductors.
  • The number of holes and electrons is therefore determined by the properties of the material itself instead of the impurities.
  • In intrinsic semiconductors, the number of excited electrons is equal to the number of holes; n = p
  • They are also termed undoped semiconductors or i-type semiconductors. Silicon and germanium are examples of the i-type semiconductor
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