A rectangular shape of stress distribution diagram at the base of a circular chimney is shown in figure. By referring to it, it may be concluded that:________

F7 Savita ENG 21-12-23 D4

This question was previously asked in
SSC JE Civil 10 Oct 2023 Shift 1 Official Paper-I
View all SSC JE CE Papers >
  1. the chimney is subjected to direct compressive stress only
  2. the chimney is subjected to wind pressure only
  3. the chimney is subjected to both bending as well as direct compressive stress 
  4. the chimney is subjected to bending stress only

Answer (Detailed Solution Below)

Option 1 : the chimney is subjected to direct compressive stress only
Free
Building Materials for All AE/JE Civil Exams Mock Test
15.5 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Explanation:

Stress distribution diagram at the base of a circular chimney:

Wind pressure(P) acting on the chimney

  • Let wind pressure(P) kN/m2 act on the left side of the chimney 
  • the height and diameter of the chimney are h and D respectively.
  • The direct stress is the same base on the chimney because the weight or load of the chimney is uniformly distributed in the base area.

\(Direct\:stress(\sigma _{d}) = \frac{Weight\:of\:Chimney(W)}{Area\:of\:chimney(A)}\)

  • Bending stress at the base of the chimney due to wind pressure  

\(Bending\:stress(\sigma _{b}) = \frac{M}{Z}\)

Where

M = Moment generated due to wind pressure

Z = Section modulus of chimney

Let the maximum stress at the base of the chimney be σmax and the minimum stress at the base of the chimney be σmin.

\(\sigma_{max} = \sigma _{d} + \sigma _{b} \\ \sigma_{max} = \sigma _{d} - \sigma _{b} \)

qImage657f4bd03153ba310b1f8ead

  • As the question σmax is equal to  σmin , we can conclude that there is no bending force occurring due to wind action and hence only force acting on base is its own dead load(direct compressive load) and the stress diagram will look like below 

F7 Savita ENG 21-12-23 D4 

Latest SSC JE CE Updates

Last updated on May 28, 2025

-> SSC JE notification 2025 for Civil Engineering will be released on June 30. 

-> Candidates can fill the SSC JE CE application from June 30 to July 21.

-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.

-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.

-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.

-> The Staff Selection Commission conducts the SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.

Get Free Access Now
Hot Links: mpl teen patti teen patti joy 51 bonus teen patti flush