Question
Download Solution PDFA steel bar (E = 200E = 200, α = 12 × 10 − 6/°C) expands by 0.3 mm due to a temperature increase. If the original length of the bar was 15 cm, what was the temperature rise?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Thermal Expansion of a Steel Bar
- Thermal expansion refers to the increase in the dimensions of a material when it is subjected to a temperature rise. For a linear material like a steel bar, this expansion can be calculated using the coefficient of linear expansion.
Given Data:
- Coefficient of linear expansion (α) = 12 × 10−6/°C
- Original length of the steel bar (L0) = 15 cm = 150 mm
- Expansion of the bar (ΔL) = 0.3 mm
Formula:
The formula for linear expansion is given by:
ΔL = α × L0 × ΔT
Where:
- ΔL = Change in length (0.3 mm)
- α = Coefficient of linear expansion (12 × 10−6/°C)
- L0 = Original length (150 mm)
- ΔT = Change in temperature (°C)
Calculation:
Rearranging the formula to solve for ΔT:
ΔT = ΔL / (α × L0)
Substituting the given values:
ΔT = 0.3 / (12 × 10−6 × 150)
ΔT = 0.3 / (1.8 × 10−3)
ΔT = 166.67 °C
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.