Question
Download Solution PDFAbhi can complete a work in 50 days. Varun is 25% more efficient than Abhi. They work together for 8 days. The remaining work is completed by Charu alone in 6\(\frac{2}{5}\)days then in how many days can Varun and Charu complete 75% of the original work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Abhi can complete a work in 50 days
Varun is 25% more efficient than Abhi
Formula Used:
Total Work = Efficiency × Time required
Calculation:
Let the efficiency of Abhi be 4 units/day
⇒ Efficiency of Varun = 4 × (125/100) = 5 units/day
As Abhi can complete a work in 50 days
⇒ Total work = 50 × 4 = 200 units
Work done by Abhi and Varun in 8 days = (4 + 5) × 8 = 72 units
Remaining work = 200 - 72 = 128 units
Charu completes 128 units in 6\(\frac{2}{5}\) days
⇒ Efficiency of Charu = 128/(32/5) = 20 units/day
75% of total work = 200 × (75/100) = 150 units
Time required by Varun and Charu to complete 150 units
⇒ 150/(5 + 20) = 6 days
∴ Varun and Charu can complete 75% of total work in 6 days.
Last updated on May 9, 2025
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