Question
Download Solution PDFAs per IS456 : 2000, what is the value of \(\frac{x_umas}{d}\)for Fe 415 steel?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The ratio of limiting depth of neutral axis to the effective depth of the beam is given by
\(X_{umax}=\left [ \frac{0.0035}{0.0055+\frac{{0.87f_{y}}}{E_{s}}} \right ]d\)
Note:
We know the standard values of the ratio of limiting depth of neutral axis to the effective depth (k) of the beam for different steel sections as following:
Xu=K .d
| Grade of Steel | Fe 500 | Fe 415 | Fe 250 |
| 'k' value | 0.46 | 0.48 | 0.53 |
For Fe415 grade limiting value of depth of neutral axis is 0.48d
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