Question
Download Solution PDFযদি ΔPQR ∼ ΔBAC হয়, ΔPQR -এ, PQ = 7 সেমি, QR = (2x - 1) সেমি এবং ΔABC-এ, AB = 14 সেমি, AC = (3x + 1) সেমি হয়, তাহলে QR এর মান কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
ΔPQR ∼ ΔBAC,
ΔPQR-এ, PQ = 7 সেমি, QR = (2x - 1) সেমি
ΔABC-এ, AB = 14 সেমি, AC = (3x + 1) সেমি
অনুসৃত ধারণা:
যদি ΔPQR ∼ ΔBAC হয় (উভয় ত্রিভুজ হল সর্বসম)
⇒ PQ / BA = QR / AC = PR / BC
গণনা:
∴ PQ / BA = QR / AC
⇒ 7 / 14 = (2x - 1) / (3x + 1)
⇒ ½ = (2x - 1) / (3x + 1)
⇒ 3x + 1 = 4x - 2
⇒ x = 3
∴ QR = (2x - 1) = (6 - 1) = 5 সেমি
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