Question
Download Solution PDFCalculate the hoop tension developed at the base of wall in a circular water tank, having diameter 12.6 m and depth of water storage 4 m. Take specific weight of water as 10 kN/m3.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given data,
Diameter (D ) = 12.6 m
depth of water storage (H) = 4m
specific weight of water (W) = 10 KN/m3
for max hoop tension (Ht)= \(W \times H \times \ \)\(D/2\)
\(H_t = 10 \times 4 \times \frac{12.6}{2} = \) 252 KN
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