Question
Download Solution PDFhe maximum interference in mm after assembly between a bush of size \(30_{ + 0.03}^{ + 0.06}\) mm and shaft of size \(30_{ - 0.02}^{ + 0.04}\) mm is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Interference fit: Interference is the difference between the size of the hole and the size of the shaft which is always negative i.e. shaft is always larger than the hole size. Here the tolerance zone of the hole will be below the tolerance zone of the shaft.
Maximum Interference = Upper limit of the shaft – Lower limit of hole
Calculation:
Given:
Hole \(30_{ + 0.03}^{ + 0.06}\) mm, Shaft \(30_{ - 0.02}^{+ 0.04}\) mm
Upper limit of shaft = 30 + 0.04 = 30.04 mm
Lower limit of hole = 30 + 0.03 = 30.03 mm
Maximum Interference = Upper limit of the shaft - Lower limit of hole
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