Question
Download Solution PDF500 mA की धारा प्रवाहित करने वाले 50 cm लंबे तार को 5 cm चौड़ाई की एक आयताकार कुंडली बनाने के लिए लपेटा जाता है। जब आयताकार कुंडली को 1.5 T के एकसमान चुंबकीय क्षेत्र के लंबवत इसकी लंबी भुजा पर रखा जाता है, तो अनुभव किया जाने वाला बलाघूर्ण ______ होता है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
विद्युत धारा, \(I=500mA=500\times10^{-3}A=5\times10^{-1}A\)
चुंबकीय क्षेत्र, \(B=1.5T\)
तार की लंबाई, L \(=50cm\)
आयताकार कुंडली की चौड़ाई \(=5cm=5\times10^{-2}m\)
The area calculated in the solution is correct. Since it is given the length of the wire. The wire is molded into a rectangle. This means the length of the wire will make perimeter of the rectangle. The breadth is given as 5. So, the length could be calculated as 2(l +b) = 50, which implies length as 20cm.
आयताकार कुंडली की लंबाई \(=20cm=20\times10^{-2}m\)
अवधारणा:
किसी धारावाही चालक का बलाघूर्ण निम्न प्रकार दिया जाता है,
- \(\tau=NIABsin\theta\)
स्पष्टीकरण:
\(\theta=90^0\) और N=1
- \(\tau=NIABsin\theta\) \(=NIABsin90^0=NIAB\)
- \(A\text { of a rectangular coil }=L\times B= 20\times5\text{ cm}^2=100\times 10^{-4} m^2\)
दिए गए सभी मानों को बलाघूर्ण के उपरोक्त समीकरण में रखने पर, हम प्राप्त करते हैं,
\(\tau=5\times10^{-1}\times100\times10^{-4}\times1.5=7.5\times10^{-3}Nm\)
अतः सही उत्तर \(\tau=7.5\times10^{-3}Nm\) है।
Last updated on May 26, 2025
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