Question
Download Solution PDFएक-दूसरे से 25 cm दूर ध्रुव वाले एक बार चुम्बक में 14.4 A-m की ध्रुव-दृढ़ता है। तो बार चुम्बक में चुम्बकीय द्विध्रुव आघूर्ण क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
- चुम्बकीय द्विध्रुव आघूर्ण: एक बार चुम्बक के लिए इसे ध्रुव दृढ़ता और दो ध्रुवों के बीच की दूरी के गुणनफल के रूप में वर्णित किया जाता है।
m = pl
जहाँ m चुम्बकीय द्विध्रुव आघूर्ण है, p ध्रुव दृढ़ता है, और I दो ध्रुवों के बीच की दूरी है।
गणना:
दिया गया है कि p = 14.4 Am; l = 25 cm = 0.25 m;
m = pl
m = 14.4 × 0.25 = 3.6 Am2
अतः सही उत्तर विकल्प 4 है।
Last updated on Jun 20, 2025
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