Question
Download Solution PDFएकल-फेज संचरण लाइन 11 kV पर 1,100 KW शक्ति का प्रसारण इकाई शक्ति गुणांक पर कर रही है। यदि इसका कुल प्रतिरोध 5 Ω है, तो संचरण लाइन की दक्षता क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
प्रसारित शक्ति (P0) = 1,100 kW
वोल्टेज (V) = 11 kV = 11,000 V
प्रतिरोध (R) = 5 Ω
शक्ति गुणांक = 1 (इकाई)
धारा (I) = \(\frac{{1,100,000}}{{11,000}} = 100\;A\)
संचरण लाइन में कुल शक्ति क्षय,
Pक्षय = I2 R
⇒ Pक्षय = (100)2 x 5 = 50 kW
निवेश शक्ति (Pin) = P0 + Pक्षय
⇒ Pin = 1,100 kW + 50 kW = 1,150 kW
\(Efficiency\left( \eta \right) = \frac{{1,100}}{{1,150}} \times 100 = 95.65 \%\)निष्कर्ष:
संचरण लाइन की दक्षता लगभग 99.10% है, जो 99.54% के सबसे निकटतम है।
Last updated on Jun 16, 2025
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