Question
Download Solution PDFΔABC, B पर एक समकोण त्रिभुज है। यदि tan A = \({{5} \over 12}\) है, तब sin A + sin B + sin C किसके बराबर होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
tan A = \({{5} \over 12}\)
गणना:
जैसा कि हम जानते हैं कि tan = P/B और sin θ = P/H
इसलिए, H = √(P2 + B2)
⇒ H = √(52 + 122)
⇒ H = √(25 + 144)
⇒ H = √169
⇒ H = 13
अब,
sin A + sin B + sin C
= sin A + sin 90° + sin C
= \({{5} \over 13}\) + 1 + \({{12} \over 13}\)
⇒ \({{5\,+\,13\,+12} \over 13}\)
⇒ \({{30} \over 13}\)
⇒ \(2{{4} \over 13}\)
∴ अभीष्ट उत्तर \(2{{4} \over 13}\) है।
Last updated on Jun 13, 2025
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