Question
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5 (sin4 θ + cos4 θ) + 3(sin6 θ + cos6 θ) + 19sin2 θ cos2 θ
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना:
प्रश्न के अनुसार:
5 (sin4 θ + cos4 θ) + 3(sin6 θ + cos6 θ) + 19sin2 θ cos2 θ can be written as:
= 5 [(sin²θ + cos²θ)² - 2sin²θcos²θ] + 3[(sin²θ + cos²θ)³ - 3sin²θcos²θ(sin²θ + cos²θ)] + 19sin²θcos²θ
इसे और हल किया जा सकता है:
= 5 (1) - 10sin²θcos²θ + 3(1) - 9sin²θ cos²θ(1) + 19sin2 θ cos2 θ
= 5 + 3 = 8
अतः, अभीष्ट मान 8 है।
Last updated on Jul 14, 2025
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