Question
Download Solution PDFयदि ∆ABC ~ ∆EDF इस प्रकार है कि AB = 6 सेमी, DF = 16 सेमी और DE = 8 सेमी है, तो BC की लम्बाई ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB = 6 सेमी, DF = 16 सेमी और DE = 8 सेमी
प्रयुक्त अवधारणा:
जब दो त्रिभुज समरूप होते हैं, तो उनके संगत कोण बराबर होते हैं और उनकी संगत भुजाएँ समानुपाती होती हैं।
गणना:
ΔABC ~ ΔEDF के रूप में,
इसलिए, AB/DE = BC/DF = AC/FE
अब,
AB/DE = BC/DF
⇒ 6/8 = BC/16
⇒ BC = (6 × 16)/8
⇒ BC = 96/8
⇒ BC = 12 सेमी
∴ BC की लम्बाई 12 सेमी है।
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