Question
Download Solution PDFयदि {(1 ÷ x) × (x3 − 2x2) + (43 ÷ 25) × x} ÷ 25 = 1, तो x के संभावित मान हैं/हैं:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है:
{(1 ÷ x) × (x3 − 2x2) + (43 ÷ 25) × x} ÷ 25 = 1
प्रयुक्त अवधारणा:
BODMAS की अवधारणा का प्रयोग किया जाता है
गणना:
= {(1 ÷ x) × (x3 − 2x2) + (43 ÷ 25) × x} ÷ 25 = 1
= \(\frac{{\frac{1}{x}(x^3-2x^2)+(\frac{4\times4\times4}{2\times2\times2\times2\times2})\times x}}{25}=1\)
= \(\frac{x^2-2x+2x}{25}=1\)
= \(x^2 = 25\)
= x = +5 या -5
⇒ इसलिए, समीकरण का मान +5 या -5 है।
Last updated on Jun 17, 2025
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