Question
Download Solution PDFयदि b = 5 है, सर्वसमिका का प्रयोग करके व्यंजक \(({5 \over b} + 5b)\) \(({25 \over b^2} - 25 + 25b^2)\) का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFb = 5
प्रयुक्त सूत्र:-
A3 + B3 =(A + B) (A2 + B2 - AB)
गणना:-
(5/b + 5b)(25/b2 - 25 +25b2)
⇒ (5/b)3 + (5b)3
उपरोक्त समीकरण में "b" का मान रखने पर
⇒ (5/5)3 + (5 × 5)3
⇒ 1 + (25)3
⇒ 1 + 15625 = 15626
∴ अभीष्ट उत्तर 15626 है।
Last updated on Jul 17, 2025
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