Question
Download Solution PDFयदि b = 5 है, सर्वसमिका का प्रयोग करके व्यंजक \(({5 \over b} + 5b)\) \(({25 \over b^2} - 25 + 25b^2)\) का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFb = 5
प्रयुक्त सूत्र:-
A3 + B3 =(A + B) (A2 + B2 - AB)
गणना:-
(5/b + 5b)(25/b2 - 25 +25b2)
⇒ (5/b)3 + (5b)3
उपरोक्त समीकरण में "b" का मान रखने पर
⇒ (5/5)3 + (5 × 5)3
⇒ 1 + (25)3
⇒ 1 + 15625 = 15626
∴ अभीष्ट उत्तर 15626 है।
Last updated on Jul 19, 2025
-> The SSC CGL Notification 2025 has been announced for 14,582 vacancies of various Group B and C posts across central government departments.
-> CSIR NET City Intimation Slip 2025 has been released @csirnet.nta.ac.in.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025 in multiple shifts.
-> Aspirants should visit the official website @ssc.gov.in 2025 regularly for CGL Exam updates and latest announcements.
-> Candidates had filled out the SSC CGL Application Form from 9 June to 5 July, 2025. Now, 20 lakh+ candidates will be writing the SSC CGL 2025 Exam on the scheduled exam date. Download SSC Calendar 2025-25!
-> In the SSC CGL 2025 Notification, vacancies for two new posts, namely, "Section Head" and "Office Superintendent" have been announced.
-> Candidates can refer to the CGL Syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline, with the age limit varying from post to post.
-> The SSC CGL Salary structure varies by post, with entry-level posts starting at Pay Level-4 (Rs. 25,500 to 81,100/-) and going up to Pay Level-7 (Rs. 44,900 to 1,42,400/-).
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.