यदि b = 5 है, सर्वसमिका का प्रयोग करके व्यंजक \(({5 \over b} + 5b)\) \(({25 \over b^2} - 25 + 25b^2)\) का मान ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 26 Jul 2023 Shift 3)
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  1. 25726
  2. 15626
  3. 15438
  4. 25636

Answer (Detailed Solution Below)

Option 2 : 15626
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दिया गया है:-

b = 5

प्रयुक्त सूत्र:-

A3 + B3 =(A + B) (A2 + B2 - AB)

गणना:-

(5/b + 5b)(25/b2 - 25 +25b2

⇒ (5/b)3 + (5b)3
 

उपरोक्त समीकरण में "b" का मान रखने पर

⇒ (5/5)3 + (5 × 5)3 

⇒ 1 + (25)3  

⇒ 1 + 15625 = 15626    

अभीष्ट उत्तर 15626 है।
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