यदि निम्नलिखित प्रत्येक स्ट्रिंग में अक्षरों को छोड़ दिया जाए और फिर शेष संख्याओं को बढ़ते क्रम में व्यवस्थित किया जाए, तो बीच में कौन-सी संख्या आएगी?

33A, 44R, 41V, 54D, 21S, C56, D46, V68, F36, G32, 61C, 47G, N55

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RRB NTPC CBT 2 (Level-5) Official Paper (Held On: 15 June 2022 Shift 3)
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  1. 41
  2. 44
  3. 54
  4. 46

Answer (Detailed Solution Below)

Option 4 : 46
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व्याख्या:

दिया गया:

  • प्रश्न में दी गई स्ट्रिंग इस प्रकार है:
    • 33A, 44R, 41V, 54D, 21S, C56, D46, V68, F36, G32, 61C, 47G, N55।
  • यदि निम्नलिखित प्रत्येक स्ट्रिंग में अक्षरों को छोड़ दिया जाता है, तो स्ट्रिंग होगी:
    • 33, 44, 41, 54, 21, 56, 46, 68, 36, 32, 61, 47, 55।
  • अब, शेष संख्याओं को बढ़ते क्रम में व्यवस्थित किया जाता है।
    • 21, 32, 33, 36, 41, 44, 46, 47, 54, 55, 56, 61, 68

अनुक्रम के मध्य में संख्या 46 है।

अत: 46 सही उत्तर है।

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