Question
Download Solution PDFयदि एक शंकु की तिर्यक ऊँचाई 60 cm है और इसके आधार की त्रिज्या 21 cm है, तो इसका वक्र पृष्ठीय क्षेत्रफल ज्ञात कीजिए। (π = \({22 \ {} \over 7}\) का प्रयोग कीजिए)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त संकल्पना:
शंकु का वक्र पृष्ठीय क्षेत्रफल = π × r × l, जहाँ r = त्रिज्या और l = तिर्यक ऊँचाई
गणना:
शंकु का वक्र पृष्ठीय क्षेत्रफल
⇒ π × r × l
⇒ π × 21 × 60
⇒ 22/7 × 21 × 60
⇒ 3960 cm2
∴ सही उत्तर 3960 cm2 है
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