यदि \(\frac{\cos \beta}{\sec \alpha}\) = 15 और \(\frac{\sin \beta}{\sec \alpha}\) = 16 है, तो sin2β का मान ___________ है।

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SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 3)
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  1. \( \frac{256}{481} \) 
  2. \(-\frac{256}{481} \)
  3. \( \frac{481}{256} \)
  4. \(-\frac{481}{256}\)

Answer (Detailed Solution Below)

Option 1 : \( \frac{256}{481} \) 
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Detailed Solution

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दिया गया है

 \(\frac{\cos \beta}{\sec \alpha}\) = 15

 \(\frac{\sin \beta}{\sec \alpha}\) = 16

गणना

Sec α = cos β/15  ......(1)

sin β = 16 × Sec α  .....(2)

समीकरण (1) का मान समीकरण (2) में रखने पर 

⇒ sin β = 16 × cos β/15

⇒ sin β/cos β = 16/15

⇒ P/B = 16/15

sin2β = P2/H2

H2 = P2 + B2

H2 = 256 + 225

H2 = 481

sin2β = 256/481

मान 256/481 है।

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