मान लीजिए कि कोण-भुजा-कोण के अंतर्गत Δ PQR और Δ STU सर्वांगसम त्रिभुज हैं। यदि ∠PQR = 60°, ∠PRQ = 30° और ∠STU = 60° है, तो ∠TSU ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 20 Jul 2023 Shift 2)
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  1. 90°
  2. 75°
  3. 60°
  4. 45°

Answer (Detailed Solution Below)

Option 1 : 90°
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दिया गया है

ΔPQR और ΔSTU सर्वांगसम त्रिभुज हैं

∠PQR = 60°, ∠PRQ = 30° और ∠STU = 60°

प्रयुक्त संकल्पना

यदि दो त्रिभुज सर्वांगसम हों, तो उनके संगत भाग बराबर होते हैं।

गणना

माना ∠TSU और ∠SUT क्रमशः y° और x° हैं।

∠QPR = 180 - (60 + 30)

∠QPR = 90°

∠QPR = 90° = ∠TSU (कोण-भुजा-कोण के अंतर्गत)

उत्तर 90° है।

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