41 से पूर्णतः विभाज्य सबसे छोटी पाँच अंकों की संख्या _______ है।

This question was previously asked in
NPCIL Assistant Grade-1 (Advance) Official Paper-II (Held On: 08 Sept, 2018)
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  1. 10041
  2. 10004
  3. 10045
  4. 10025

Answer (Detailed Solution Below)

Option 2 : 10004
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NPCIL Assistant Grade 1 Computer Knowledge Subject Test - 01
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गणना:

सबसे छोटी पाँच अंकों की संख्या = 10000

जब हम 10000 को 41 से विभाजित करते हैं तो शेषफल 37 प्राप्त होता है

इसलिए, सबसे छोटी पाँच अंकों की संख्या जो 41 का गुणज है:

10000 + (41 - 37) = 10000 + 4 = 10004

∴ सही उत्तर विकल्प 2) है।

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