Question
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का मान है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
अवधारणा:
गणना:
I =
यहां
फिर आंशिक भिन्न की अवधारणा लागू करने पर
अब हरों का वज्र गुणन करने पर
1 = A(x - 1) + B(2x + 3)
गुणांक की तुलना करने पर
A + 2B = 0 और 3B - A = 1
दोनों को जोड़ने पर हमें व्यंजक प्राप्त होता है
5B = 1 ⇒ B =
अब अभिव्यक्ति में B का मान रखें तो हमें प्राप्त होता है
अब, पूर्णांक है
अब 2x + 3 = u के स्थान पर 2x dx = du रखने पर
प्रतिस्थापन पूर्ववत करने पर u = 2x + 3
अतः विकल्प (3) सही है।
Last updated on Jun 19, 2025
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