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निर्देश : निम्नलिखित प्रश्नों के लिए निम्नलिखित पर विचार करें:
परवलय y2 = kx और रेखा x = k, जहाँ k > 0 है, द्वारा परिबद्ध क्षेत्रफल 4/3 वर्ग इकाई है।
नाभिलम्ब द्वारा परिबद्ध परवलय का क्षेत्रफल क्या है?
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दिया गया है:
परवलय y2 = kx और रेखा x = k, जहाँ k > 0, द्वारा परिबद्ध क्षेत्रफल 4/3 वर्ग इकाई है
परिबद्ध क्षेत्रफल = 4/3 वर्ग इकाई
= \(2 \int_0^kydx\)
⇒ 4/3 = \(2 \int_0^k\sqrt k \sqrt xdx\)
⇒1 = k2
⇒ k = ±1 (चूँकि k>0)
⇒ k = 1
इसलिए परवलय का समीकरण है y2 = x
⇒ 4a = 1
⇒ a = 1/4
परवलय y2 = x और नाभिलम्ब x = 1/4 का क्षेत्रफल है
= \(2 \int_0^\frac{1}{4}\sqrt x dx = 2\times \frac{2}{3}\times(\frac{1}{4})^\frac{3}{2}\)
= 1/6 वर्ग इकाई
∴ विकल्प (a) सही है
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