Question
Download Solution PDFk का मान क्या है जिसके लिए सदिश k(2î - ĵ - 2k̂) की 6 इकाई लंबाई है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
मूल से सदिश \(\rm a\hat{i} + b\hat{j} + c\hat{k} \) की लंबाई \(\rm \sqrt{a^{2} + b^{2} + c^{2}}\) है
गणना:
मूल से सदिश k(2î - ĵ - 2k̂) की लंबाई इस प्रकार है
\(\rm \sqrt{(2k)^{2} + (-k)^{2} + (-2k)^{2}}\)
= \(\rm \sqrt{4k^{2} + k^{2} + 4k^{2}}\)
= \(\rm \sqrt{9k^{2} }\)
= 3k
लंबाई 6 इकाई दी गई है
3k = 6
k = 6/3
k = 2
इसलिए विकल्प 2 सही है।
Last updated on Jun 20, 2025
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