निम्नलिखित में से कौन एक अपरिमेय संख्या है?

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. √7 − 8
  2. (√5 + 1) (√5 − 1)

Answer (Detailed Solution Below)

Option 3 : √7 − 8
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Bihar STET Paper 1 Mathematics Full Test 1
150 Qs. 150 Marks 150 Mins

Detailed Solution

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गणना:

 = 1.2 (कोई अपरिमेय संख्या नहीं)

 =  0.8i ( परिमेय संख्या, एक अपरिमेय संख्या नहीं है।)

(√5 + 1) (√5 − 1) = 5 - 1 = 4 (a2 - b2 = (a - b)(a + b) के द्वारा (यह परिमेय संख्या है।)

√7 − 8 = अपरिमेय संख्या 

अतः, सही उत्तर विकल्प 3 है।

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