If (a + 1)2 + (a + 2)2 = 16 then what is the value of 40 + 12a + 4a2?

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SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 4)
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  1. 56
  2. 62
  3. 74
  4. 52

Answer (Detailed Solution Below)

Option 2 : 62
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Detailed Solution

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Given:

(a + 1)2 + (a + 2)2 = 16

Calculation:

(a + 1)2 + (a + 2)2 = 16

a2 + 1 + 2a + a2 + 4 + 4a = 16

2a2 + 6a + 5 = 16

2a2 + 6a = 11

Multiply by 2 on both sides

4a+ 12a = 22

Add 40 both sides

4a2 + 12a + 40 = 62

Option 2 is the correct answer.

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