If (X - \(\rm \frac{1}{x}\)) = 6, and x > 0, find the value of (x2 - \(\rm \frac{1}{x^2}\)).

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SSC CGL 2023 Tier-I Official Paper (Held On: 20 Jul 2023 Shift 4)
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  1. 12\(\sqrt{10}\)
  2. 18\(\sqrt{10}\)
  3. 24\(\sqrt{2}\)
  4. 24\(\sqrt{10}\)

Answer (Detailed Solution Below)

Option 1 : 12\(\sqrt{10}\)
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
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Detailed Solution

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Given

x - 1/x = 6

Formula Used

x + 1/x = √ ((x - 1/x)2 + 4)

x2 - 1/x2 = (x - 1/x)(x + 1/x)

Calculation:

x - 1/x = 6

x + 1/x = √ ((x - 1/x)2 + 4)

x + 1/x = √(40)

⇒ x + 1/x = 2√10

x2 - 1/x2 = (x - 1/x)(x + 1/x)

= 2√10 × 6

= 12√10

The answer is 12√10

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