Question
Download Solution PDFIf (x + y + z) = 23 and x2 + y2 + z2 = 179, then find the value of (xy + yz + zx).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
If (x + y + z) = 23 and x2 + y2 + z2 = 179, then find the value of (xy + yz + zx).
Formula used:
(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)
Calculation:
(x + y + z)2 = 232 = 529
x2 + y2 + z2 = 179
So, 529 = 179 + 2(xy + yz + zx)
⇒ 529 - 179 = 2(xy + yz + zx)
⇒ 350 = 2(xy + yz + zx)
⇒ 350/2 = xy + yz + zx
⇒ xy + yz + zx = 175
∴ The correct answer is option (3).
Last updated on Jun 3, 2025
-> The Staff Selection Commission has officially released the SSC Selection Post Phase 13 Notification 2025 on its official website at ssc.gov.in.
-> A total number of 2423 Vacancies have been announced for various selection posts under Government of India.
-> The Computer Based Exam is scheduled from 24th July to 4th August, 2025. Candidates will be able to apply online from 2nd June 2025 to 23rd June 2025.
-> The SSC Selection Post Phase 13 exam is conducted for recruitment to posts of Matriculation, Higher Secondary, and Graduate Levels.
-> The selection process includes a CBT and Document Verification.
-> Some of the posts offered through this exam include Laboratory Assistant, Deputy Ranger, Upper Division Clerk (UDC), and more.
-> Enhance your exam preparation with the SSC Selection Post Previous Year Papers & SSC Selection Post Mock Tests for practice & revision.