Question
Download Solution PDFIn a series RLC circuit, the total impedance is minimum when _______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFSeries Resonance
A series RLC circuit exhibits resonance when the inductive and capacitive reactances are equal in magnitude but opposite in phase, resulting in a purely resistive impedance, and the value of impedance is minimum.
The impedance of the series RLC circuit is given by:
\(Z=\sqrt{R^2+(X_L^2-X_C^2)}\)
At XL = XC
\(Z=\sqrt{R^2+(X_L^2-X_L^2)}\)
Z = R
The impedance value is minimum.
Last updated on Jun 16, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.