Question
Download Solution PDFIn a UJT relaxation oscillator, the value of RBB is 5 kΩ and stand off ratio n = 0.6 at IE = 0. The value of RB2 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Intrinsic stand-off ratio (η): It is the ratio of RB1 to the sum of RB1 and RB2. It can be expressed as
\(η = \frac{{RB1}}{{RB1 + RB2}} = \frac{{RB1}}{{R_{BB}}}\)
The typical range of the intrinsic standoff ratio is from 0.4 to 0.8.
RBB: It is the resistance between terminals B1 and B2. In simple words, it is the resistance of the N-Type bar when measured lengthwise. If RB1 is the resistance of the bar from E to B1 and RB2 is the resistance of the bar from E to B2, then RBBO can be expressed as
RBB= RB1 + RB2.
The typical range of RBB is from 3 kΩ to 10 kΩ.
UJT pin diagram:
UJT circuit diagram:
Calculation:
Given that, RBB = 5 kΩ and \(\eta\)=0.6
∴ intrinsic stand-off ratio (η) can be calculated as
\( \eta = \frac{{RB_1}}{{\left( {RB_1+RB_2} \right)k}} = \frac{{RB_1}}{{\left( {RBB} \right)k}}\) ..................(1)
\(0.6=\frac{RB_1}{5}\)
RB1 = 3 kΩ
Putting in equation 1, we get
RB2 = 2 kΩ
Last updated on May 8, 2025
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